I have noticed some unexpected behaviour with method chaining. Specifically I have a class A from which I want to call the static method to create class B:
classdef A
methods (Static)
function b = getB(args)
b = B(args);
end
end
end
And then I want to use class B to do something e.g. use the print() method, where class B is:
classdef B
properties
Property1
end
methods
function self = B(args)
self.Property1 = args;
end
function print(self)
fprintf(self.Property1);
end
end
end
Trying
A.getB(args).Property1
succeeds.
I would thus also expect
A.getB(args).print()
to succeed, however, it gives the error:
Not enough input arguments.
Error in A.getB (line 5)
b = B(args);
Would anyone have any suggestions on why this is so? Thanks very much in advance.

 Réponse acceptée

Philip Borghesani
Philip Borghesani le 20 Déc 2017
In general indexing into the output of a function call, what you call method chaining is not supported in MATLAB. Property access currently works on the output of a static function but function calls in general do not. You may find that your code behaves differently on different versions of MATLAB.
Try
A.getB(args).print; % works because it looks like property access, not recommended
print(A.getB(args)); % will work
obj=A.getB(args); obj.print(); % or print(obj) will also work

5 commentaires

Thanks for this explanation Philip. I have noticed that when I make getB a non-static method and then call it from an instance of A, i.e:
a = A()
a.getB(args).print()
This works. Could you also give some insights into why this is so?
It's not static vs nonstatic method that makes the difference it is static call vs call on an object. Even if getB is static then:
a=A();
a.getB(args).print() % or
A().getB(args).print() %works
a=A();a.getB is simpler to parse then A.getB because from code analysis it is obvious that a is a variable so getB(args) must be a property access or method call but A.getB(args) could also be a call to the static method getB in the package A.
Benjamin Chen
Benjamin Chen le 20 Déc 2017
That sounds reasonable, thanks. I wish the error message could have been this informative rather than just "Not enough input arguments".
Philip Borghesani
Philip Borghesani le 20 Déc 2017
I agree, the error message should have been better.
This appears to be fixed so that a static call works correctly in a future version of MATLAB.
Benjamin Chen
Benjamin Chen le 20 Déc 2017
That's great news, looking forward to it!

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Plus de réponses (1)

Image Analyst
Image Analyst le 19 Déc 2017
fprintf(self.Property1);
needs two inputs, a format string, and a variable. You only passed it the variable without passing it a format specifier string like '%f\n' or something (depends on the type of variable you want to print).
fprintf('The value = %f\n', self.Property1);

1 commentaire

Benjamin Chen
Benjamin Chen le 19 Déc 2017
Thanks for the answer Image Analyst. It seems the error is not at the fprintf part, but in the static getB method of class A.
Even if I replace the fprintf with disp, it still gives the same error.

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