Comparing images using morphological operations only

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koks paul
koks paul le 22 Déc 2017
Commenté : Image Analyst le 23 Déc 2017
I have to detect numbers on license plate through comparing them with the digits numbers images, only using morphology, but i get stuck after segmenting the digits and while comparing both images "9 from plate & 9 original image" ANDing gives me partially wrong answer
% max = -99999;
% bothTrue = IMG & One;
% NumPixels = sum(bothTrue(:));
% if NumPixels>max
% max=NumPixels;
% Digit=1;
% end
and getting the near "Extent area" fails also
min=100000;
A=sqrt((0.4913)^2-Anum^2); //this number i observed from the extent of image of digit"1"
if A<min
Digit=1;
min=A;
end
So is there someway to solve it using morph and logical operations only?
  2 commentaires
Stephen23
Stephen23 le 22 Déc 2017
@koks paul: this is not twitter. I removed the ugly # characters from your tags, and separated them correctly using commas.
koks paul
koks paul le 22 Déc 2017
Modifié(e) : koks paul le 22 Déc 2017
Thank you for making it look better, any help for the question itself?

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Réponses (2)

Walter Roberson
Walter Roberson le 22 Déc 2017
No. The calculation
A=sqrt((0.4913)^2-Anum^2);
is not a morphological calculation.
Morphological operations transform one matrix to another matrix, but morphological operations never make decisions about what the input or output matrices mean. You always need a non-morophological operation to interpret the results of the transformation.
  2 commentaires
koks paul
koks paul le 22 Déc 2017
Ok, good. Now i need to compare the segmented number, with the 9 numbers to decide what's the digit i got. What shall i use?

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Image Analyst
Image Analyst le 22 Déc 2017
I don't know how to do it using morphology (dilation, erosion, opening, and closing). You can do it using logical operations (and, or, exclusive or, not). Try using the Dice Sorensen coefficient (demo attached).
  1 commentaire
koks paul
koks paul le 23 Déc 2017
it's not so much what i want to do, but thanks anyways

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