Multiplication of cell arrays

34 vues (au cours des 30 derniers jours)
lucksBi
lucksBi le 17 Jan 2018
Commenté : lucksBi le 17 Jan 2018
hey
i have following four cell arrays(2x7 cell). i want to multiply all four. Like cell1 of a with cell 1 of b,c,d and same for all cells.
a = {[],[0.13,0.13],1.13,[0.13,0.1,1.13],[0.13,1.1,0.13],[],[]; [],[],[-1.72,-0.72,1.2],0.27,[],[0.27,1.2],[-1.7,0.2,-0.7,1.28]}
b= {[],[-0.4,-0.4],-0.2,[-0.4,-0.4,1.8],[-1.28,-1.2,0.78],[],[]; [],[],[-2.2,-1.2,0.7],0.5,[],[-0.09,-1.0],[-0.31,0.6,-2.3,1.6]}
c= {[],[1,1],1,[1,1,1],[1,1,1],[],[]; [],[],[1,1,1],1,[],[1,1],[1,1,1,1]}
d= {[],[1,1],1,[1,1,1],[1,1,1],[],[]; [],[],[1,1,1],1,[],[1,1],[1,1,1,1]}
I have used:
for x=1:2
for y=1:7
mul{x,y}=cellfun(@(x,y,z,s) x.*y.*z.*s, a{x,y},b{x,y},c{x,y},d{x,y},'UniformOutput', false);
end
end
which gives following error:
Input #2 expected to be a cell array, was double instead.
Also these arrays doesn't only contain two rows.
kindly help

Réponse acceptée

Jan
Jan le 17 Jan 2018
cellfun is smart, but harder to debug than a simple loop.
mul = cell(2, 7);
for x=1:2
for y=1:7
mul{x,y} = a{x,y} .* b{x,y} .* c{x,y} .* d{x,y};
end
end
Does this work? I assume if fails with the same error. Then use the debugger:
dbstop if error
Run the code again until it stops at the error. Now check the sizes:
size(a{x,y})
size(b{x,y})
size(c{x,y})
size(d{x,y})
  1 commentaire
lucksBi
lucksBi le 17 Jan 2018
yea dbstop helped. Thank You

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 17 Jan 2018
Remove the loop.
mul = cellfun(@(x,y,z,s) x.*y.*z.*s, a, b, c, d, 'uniform', 0);
  1 commentaire
lucksBi
lucksBi le 17 Jan 2018
ThankYou. It works fine of two rows but on matrix of 8x7 it gives following error:
All of the input arguments must be of the same size and shape. Previous inputs had size 1 in dimension 1. Input #3 has size 8

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