system response
10 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi everyone, i am trying to obtain a response of a first order system to a step input, however the output the graph depicts doesn't match with what i expected. would someone be kind enough to give me a push in the right direction. the script for the program is thus:
clear all clc k1 = 2e4; k2 = 2e7; k3 = 2e4; c = 2e10; num= [(k1*c) (k1*k2)]; den= [(c*k1*k3) (k1*k2*k3)]; P=tf(num,den); display (P) step (P), grid title('y3 with a step input') %ylim([0 1])
Regards
0 commentaires
Réponse acceptée
Arkadiy Turevskiy
le 8 Mai 2012
Your system P, as defined, is simply a gain. You can see that if you do
zpk(P)
ans =
5e-05 (s+0.001)
---------------
(s+0.001)
You can even see it if you look carefully at your num and den formulas:
num = k1*c*s+k1*k2 =k1*(c*s+k2)
den = c*k1*k3*s+k1*k2*k3 = k1*k3*(c*s+k2)
Therefore
num/den = k1* (c*s+k2) / (k1*k3* (c*s+k2)) = 1/k3
This is exactly what you see when you look at step response.
In short, recheck your formulas.
Arkadiy
2 commentaires
Arkadiy Turevskiy
le 9 Mai 2012
the system is simply a gain, so it is stable. You need to recheck your formulas, most likely there is an error in how you calculate num and den.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Time and Frequency Domain Analysis dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!