Effacer les filtres
Effacer les filtres

Sysmsum gives wrong output

2 vues (au cours des 30 derniers jours)
Mohamed Musni
Mohamed Musni le 23 Jan 2018
Commenté : Stephen23 le 23 Jan 2018
For this code im getting output as below. But its multiplied with 3 in every term. What am I doing wrong here? Because I don’t need that multiplication with 3
  1 commentaire
Stephen23
Stephen23 le 23 Jan 2018
@Mohamed Musni: please do not post screenshots. It is actually easier for us when you post real text: this includes the code and any error messages. Real text can be searched (or searched for), edited, and run. Screenshots are basically useless in most cases.

Connectez-vous pour commenter.

Réponse acceptée

Birdman
Birdman le 23 Jan 2018
Actually, your code displays the correct output because you try to implement the series sum with respect to a different variable k, which is not included in any of your other symbolic variables. Therefore your series turns into something that multiplying a constant value with m, which is 3 in this case.
((((q.*t)./2).*h)+P)./t
>> [q1 + 10, (3*q2)/2 + 10, 2*q3 + 10]
As you see, q symbolic variable is not dependent on k, therefore your symsum will be multiplied by m directly. 3 comes from that.
symsum(((((q.*t)./2).*h)+P)./t,k,1,m)
>> [3*q1 + 30, (9*q2)/2 + 30, 6*q3 + 30]
  3 commentaires
Birdman
Birdman le 23 Jan 2018
Yes, you can change the upper limit dependent on k as follows:
symsum(((((q.*t)./2).*h)+P)./t,k,1,m+k)
Mohamed Musni
Mohamed Musni le 23 Jan 2018
Thank you. have a nice day :D

Connectez-vous pour commenter.

Plus de réponses (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by