Bug in Persistent variables? Simulink M-function
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I am unable to initialize a Persistent variable. Here's a snippet of code in a Simulink M-function which does not actually set 'a' no matter what I do:
persistent a
if isempty(a)
a = 1;
end
Either printing out 'a' or evaluating 'a' gives
a=[]
...NOT a=1 as it should.
It doesn't matter what the variable name is, or what I try to set it to, or how many variables there are. This bug happens with two different sets of Persistent Variables.
However, oddly, later on in the SAME M-function, I do another persistent declaration using the exact same method and there initialization DOES work.
I tried this in both R2016a and 2017b
What is going on?
4 commentaires
John Pryce
le 25 Mai 2019
Modifié(e) : John Pryce
le 25 Mai 2019
This bug exists. My "main program" is a function with input arguments and the crash occurs some levels down inside an a function that is called by fzero(), so isolating the error was tricky.
I confirm what John says "It doesn't matter what the variable name is, or what I try to set it to". Further:
- If it crashes and I immediately re-run with the same inputs it always goes on crashing.
- If I then run with different inputs it may work correctly.
- If after doing something else I re-run with the original inputs that caused the crash it may work correctly.
- Changing the layout of code, or changing nearby code, may change it between working and crashing. E.g. I originally had if nargin>4, it = it0; end below, and changing it to what's written cured the problem – so I thought! But it reappeared with other inputs.
- Stepping through in the debugger, with argument it0 absent so nargin>4 is false, I found that though it skipped the it = it0; statement, it nonetheless changed the value of it to an unpredictable value (e.g. 165) while going from if to end.
- Once past this perilous initialisation, it seems it behaves as it should do.
The piece of code in question is
function [x,xp,it1] = searchAndInterp(tt,xx,xxp,t,it0)
% some comments
persistent it %Seems most economical way to implement this
itbefore=it %!!!DEBUGGING
if nargin>4
it = it0;
end
if isempty(it), it=1; end
itafter=it %!!!DEBUGGING
%...
That evidence should help locate where in the compiler the error is located. I have a file of relevant command window output but can't see how to attach it.
I'm using
-----------------------------------------------------------------------------------------------------
MATLAB Version: 9.5.0.944444 (R2018b)
Operating System: Mac OS X Version: 10.14.4 Build: 18E226
Java Version: Java 1.8.0_152-b16 with Oracle Corporation Java HotSpot(TM) 64-Bit Server VM mixed mode
-----------------------------------------------------------------------------------------------------
John
le 25 Mai 2019
amin ya
le 29 Jan 2020
I can confirm that this is a bug. I am on Matlab 2019b Update 3
John
le 29 Jan 2020
Réponses (1)
John
le 31 Jan 2018
2 commentaires
Youssef Ismail
le 8 Sep 2022
I also have the same problem has it been solved?
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