can you explain someone, how to create a channel matrix for visible light communication

i don't know,how to develope the channel matrix for visible light communication. but i know the channel matrix of normal awgn channel,rayleigh and rician channel.

[Rik]

Have a read here and here. It will greatly improve your chances of getting an answer.

Answer 1

[Abhishek Ballaney]

https://in.mathworks.com/help/phased/ref/scatteringchanmtx.html

Answer 2

[abdullah qasim]

clear
clc
theta=70;
% semi-angle at half power
m=-log10(2)/log10(cosd(theta));
%Lambertian order of emission
P_total=2000;
%transmitted optical power by individual LED
Adet=1e-4;
%detector physical area of a PD
Ts=1;
%gain of an optical filter; ignore if no filter is used
index=1.5;
%refractive index of a lens at a PD; ignore if no lens is used
FOV=60*pi/180;
%FOV of a receiver
G_Con=(index^2)/sin(FOV);
%gain of an optical concentrator; ignore if no lens is used
lx=5; ly=5; lz=3;
% room dimension in metre
h=2.15;
%the distance between source and receiver plane
%[XT,YT]=meshgrid([?1.25 1.25],[?1.25 1.25]);
XT=0; YT=0;
% position of LED;
Nx=lx*10; Ny=ly*10;
% number of grid in the receiver plane
x=-lx/2:lx/Nx:lx/2;
y=-ly/2:ly/Ny:ly/2;
[XR,YR]=meshgrid(x,y);
% receiver plane grid
D1=sqrt((XR-XT(1,1)).^2+(YR-YT(1,1)).^2+h^2);
% distance vector from source 1
cosphi_A1=h./D1;
% angle vector
H_A1=(m+1)*Adet.*cosphi_A1.^(m+1)./(2*pi.*D1.^2);
% channel DC gain for source 1
P_rec=P_total.*H_A1.*Ts.*G_Con;
% received power from source 1;
P_rec_dBm=10*log10(P_rec);
surfc(x,y,P_rec_dBm);
% contour(x,y,P_rec_dBm);hold on
%mesh(x,y,P_rec_dBm);
%meshc(x,y,P_rec_dBm);
xlabel('X (m)');
ylabel('Y (m)');
zlabel('Received power (dBm)');
axis([-lx/2 lx/2 -ly/2 ly/2 min(min(P_rec_dBm)) max(max(P_rec_dBm))]);