Replace String Value in Cell with Numerical Value
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Hi all
I like to replace a string value in a cell with a numerical value.
The cell looks like:
A1 = {-1,0,0,0,0,0,0;1,-1,0,0,-1,0,0;0,1,1,-1,0,0,0;0,1,1,-1,0,0,0;0,0,1,0,0,0,0;0,0,0,'C.C4',0,0,0;0,0,0,0,1,1,-1;0,0,0,0,0,1,0;0,0,0,0,0,0,'C.C5'}
I like to replace the string C.C4 and C.C5 with numerical values like: C.C4 = 2; C.C5 = 3;
I already burnt hours on this problem! Thanks a lot for your help (-:
Cheers, Chris
1 commentaire
Guillaume
le 16 Fév 2018
Why does 'C.C4' get replaced by 2 and 'C.C5' by 3 (instead of 4 and 5 or something more logical)?
Réponse acceptée
Stephen23
le 19 Fév 2018
Modifié(e) : Stephen23
le 19 Fév 2018
A = {'Inf','C.C3','C.C2',1;'-Inf',1,'C.C5','Inf';'C.C4',0,0,'-Inf';0,0,1,'-Inf'};
idn = cellfun(@isnumeric,A); % identify numeric values.
out = nan(size(A)); % preallocate output matrix.
out(idn) = [A{idn}]; % allocate numeric values.
tmp = A(~idn); % subset with char vectors.
vec = str2double(tmp); % attempt to convert to numeric.
idx = isnan(vec); % identify char not converted.
C = {'C.C2','C.C3','C.C4','C.C5','C.C6'};
V = [ 10, 100, 34, 35, 100];
[idm,idc] = ismember(tmp(idx),C); % lookup table.
assert(all(idm),'Not in C:%s',sprintf(' %s,',C{~idm}))
vec(idx) = V(idc);
out(~idn) = vec
giving this numeric matrix:
out =
Inf 100 10 1
-Inf 1 35 Inf
34 0 0 -Inf
0 0 1 -Inf
An alternative to throwing an error for missing C.Cx strings would be to put a NaN in that position:
[idm,idc] = ismember(tmp(idx),C) % lookup table.
tmp = nan(size(idc));
tmp(idm) = V(idc(idm))
vec(idx) = tmp;
out(~idn) = vec
Plus de réponses (1)
Guillaume
le 16 Fév 2018
Identifying the char elements is easy. And once the rule for replacing them by numbers is known, replacing them is also easy:
toreplace = cellfun(@ischar, A1);
A1(toreplace) = num2cell((1:sum(toreplace(:))) + 1) %arbitrary rule that replace char arrays by numbers 2, 3, 4, ...
After that you probably want
A1 = cell2mat(A1)
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