How to read images in a folder

I am a student and I need to find the code to read the images in a file in order to do cropping. In here I named my images as

 user001-01.bmp
 user001-02.bmp etc.

I need help for this because I'm a beginner to MATLAB.

[Maria Ramirez]

oof=cd; % this corresponds to your current folder

nf=(fullfile(cd,' put here the name of your folder')); %this means the new folder where you created it

cd(nf) names=dir; names=names(1:end); % it depends on where the folder starts

hh=length(names);

for idx=1:hh

v(idx).names=names(idx).name;

end % the new vector that got the fields

for idx=1:hh

name=v(idx).names;

img=imread(name);

% you can delete this, this only graphs the images

imshow(img)

drawnow %

% Here you put the respectively code, depends on what do you want to do with the images

end %this returns you to the current folder, where you started

cd(oof)

Created by SMC

[Stephen23]

@Maria Ramirez: using cd like that is slow and makes debugging harder, and should be avoided: it is recommended to simply use fullfile to access data files in other directories, to make code more efficient and easier to debug. Note that in your code there is no point in transferring the filenames from the structure names to the structure v, or even in using two separate for loops. You should also use a match string when calling dir, as otherwise it will return the names of all files in the directory, even if they are not the correct type for processing.

So a simpler, more efficient, more robust version of your code would be something like this:

D = 'directory where the files are saved';
S = dir(fullfile(D,'name*.jpg')); % pattern to match filenames.
for k = 1:numel(S)
    F = fullfile(D,S(k).name);
    I = imread(F);
    imshow(I)
    S(k).data = I; % optional, save data.
end

You might like to take a look at the examples in the documentation:

https://www.mathworks.com/help/matlab/import_export/process-a-sequence-of-files.html

[Lenin Falconi]

Thanks it worked fine. I was struggling with a code using ls which worked fine in Windows but it didn't work in Ubuntu because it delivers a char of 1xall chars in directory...

[vikram punia]

Thanks, Really helped.

[Rijal Fadilah Tsalis]

its very helpfull

Answer 1

[Michelle Hirsch]

Nilushi -

We won't be able to hand you a complete answer, but can give some pointers. Here's a code snippet that shows common patterns for reading data from files. There are a bunch of concepts you are going to want to learn about to understand this code:

• Working with structures. When you get a list of image files, their names will be stored inside of a structure.
• Working with cell arrays. We'll use a cell array to store the data coming from the different images, since it allows for each image to be a different size. If you happen to know that all of your images are exactly the same size you can use a regular numeric array instead.

% Get list of all BMP files in this directory
% DIR returns as a structure array.  You will need to use () and . to get
% the file names.
imagefiles = dir('*.bmp');      
nfiles = length(imagefiles);    % Number of files found

for ii=1:nfiles
   currentfilename = imagefiles(ii).name;
   currentimage = imread(currentfilename);
   images{ii} = currentimage;
end

Best of luck! - scott

[Nilushi Dissanayake]

thank you very much for the quick reply,, i will try these code with my work

[Falak Shah]

Thanks a lot.. It was really useful info for me too..

[KARTHIK RAJESH]

Thanks

[ayushi]

thanx it worked but madam what i have to do if i want to fed those all images to a folder one by one ?? and repeat execution of thefunction until and unless each and every images executes within the function??

[Tong Liang]

Awsome!!!

[Zoe]

OMG THANK YOU SO MUCH!!

[Muhammad Shahzaib]

Its worked like charm, thanks!

[Haritha GB]

Thank you so much!! Does anyone know where I could read up more about cell arrays and structures?

[Hasaan Ijaz]

Worked for me as well. Thank you!

[Javaid Iqbal]

Thanks a lot

Answer 2

[Sebastian]

There might be different ways to do this. An easy one is

for a = 1:10
   filename = ['user001-' num2str(a,'%02d') '.bmp'];
   img = imread(filename);
   % do something with img
end

[Nilushi Dissanayake]

thank you very much,, i really appreciated,,

[Tong Liang]

Yeah, this is what I would usually do. But, this method won't work if the filenames of the images don't fit into a certain pattern

[artprakasa]

yeaayy.. thanks, good idea.

[Liu Sam]

Thank you! This is the exact answer I want!

Answer 3

[Walter Roberson]

Please check the FAQ on this topic

[Nilushi Dissanayake]

thank you very much,,

Answer 4

[George]

You can try ImageDatastore

[Harpreet Kaur]

but it only works in 2015b and above. is there any alternative to ImageDatastore?

[Walter Roberson]

To be slightly more accurate, the imageDatastore function needs R2016a or later, but the imageDatastore class was introduced in R2015b and objects could be created by calls to datastore.

[Walter Roberson]

Before R2015a, the closest equivalent was the dataset array from the Statistics toolbox.