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How to read images in a folder

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Nilushi Dissanayake
Nilushi Dissanayake le 25 Jan 2011
Réponse apportée : DGM le 24 Juin 2023
I am a student and I need to find the code to read the images in a file in order to do cropping. In here I named my images as
user001-01.bmp
user001-02.bmp etc.
I need help for this because I'm a beginner to MATLAB.
  7 commentaires
naila
naila le 24 Juin 2023
hi,
i have some jpeg images in a folder (saved in C drive),using imread command in matlab 2018 but its not working.
please help me out.
Image Analyst
Image Analyst le 24 Juin 2023
If you have any more questions, then attach your image and code to read it in with the paperclip icon after you read this:
Do it in your own new question rather than here in @Nilushi Dissanayake's question. And "not working" is so vauge as to be unanswerable. Explain what that means, like give us ALL the red text.

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Réponse acceptée

Michelle Hirsch
Michelle Hirsch le 25 Jan 2011
Nilushi -
We won't be able to hand you a complete answer, but can give some pointers. Here's a code snippet that shows common patterns for reading data from files. There are a bunch of concepts you are going to want to learn about to understand this code:
  • Working with structures. When you get a list of image files, their names will be stored inside of a structure.
  • Working with cell arrays. We'll use a cell array to store the data coming from the different images, since it allows for each image to be a different size. If you happen to know that all of your images are exactly the same size you can use a regular numeric array instead.
% Get list of all BMP files in this directory
% DIR returns as a structure array. You will need to use () and . to get
% the file names.
imagefiles = dir('*.bmp');
nfiles = length(imagefiles); % Number of files found
for ii=1:nfiles
currentfilename = imagefiles(ii).name;
currentimage = imread(currentfilename);
images{ii} = currentimage;
end
Best of luck! - scott
  10 commentaires
Hasaan Ijaz
Hasaan Ijaz le 12 Sep 2020
Worked for me as well. Thank you!
Javaid Iqbal
Javaid Iqbal le 28 Fév 2022
Thanks a lot

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Plus de réponses (4)

Sebastian
Sebastian le 25 Jan 2011
There might be different ways to do this. An easy one is
for a = 1:10
filename = ['user001-' num2str(a,'%02d') '.bmp'];
img = imread(filename);
% do something with img
end
  4 commentaires
artprakasa
artprakasa le 13 Mar 2017
yeaayy.. thanks, good idea.
Liu Sam
Liu Sam le 4 Mar 2018
Thank you! This is the exact answer I want!

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Walter Roberson
Walter Roberson le 25 Jan 2011
Please check the FAQ on this topic
  1 commentaire
Nilushi Dissanayake
Nilushi Dissanayake le 25 Jan 2011
thank you very much,,

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George
George le 24 Sep 2016
You can try ImageDatastore
  3 commentaires
Walter Roberson
Walter Roberson le 11 Sep 2017
To be slightly more accurate, the imageDatastore function needs R2016a or later, but the imageDatastore class was introduced in R2015b and objects could be created by calls to datastore.
Walter Roberson
Walter Roberson le 11 Sep 2017
Before R2015a, the closest equivalent was the dataset array from the Statistics toolbox.

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DGM
DGM le 24 Juin 2023
There are already many examples that I don't need to repeat, but I have my own ways of doing things. I'm only throwing this here because this is a defacto reference question.
Pay particular note to the latter part of the answer.

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