Structs fields indexing issue

2 vues (au cours des 30 derniers jours)
Lask
Lask le 7 Mar 2018
Commenté : Jos (10584) le 7 Mar 2018
Hi,
I have a structure 'Parent', which stores three structs named 'Child1','Child2' and 'Child3' (these structs have the same fields with different values). I would like to know how to find if any of those 3 structs matches a condition. For example, something like:
find(Parent.*.field_1 == 2)
any help would be appreciated.

Réponse acceptée

Stephen23
Stephen23 le 7 Mar 2018
Modifié(e) : Stephen23 le 7 Mar 2018
If all of the child structures have exactly the same fields then you would be much better off using a non-scalar structure instead of nested structures:
S(1).field = ...
S(2).field = ...
S(3).field = ...
Then you could trivially do this:
find([S.field] == 2)
Using a non-scalar structure would make your code much simpler and more efficient.
  1 commentaire
Jos (10584)
Jos (10584) le 7 Mar 2018
While Stephen is absolutely right about the benefits of using an array of structures, take note that this concatenation would yield different indices from applying find on each structure element separately:
A(1).f = [1 2] ;
A(2).f = [2 3 2] ;
find([A.f]==2) % → 2 3 5 !
[find(A(1).f==2) find(A(2).f==2)] % → 2 1 3 !

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Jos (10584)
Jos (10584) le 7 Mar 2018
Parent.Child1.field_1 = [1 2 2 3] ;
Parent.Child2.field_1 = [1 3 3 2 3 2] ;
Parent.Child3.field_1 = [2] ;
A = structfun(@(S) find(S.field_1==2), Parent, 'un', 0)
A = horzcat(A{:})

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