Rotate 1 by N vector

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Peter Popoola
Peter Popoola le 8 Mar 2018
Commenté : Jan le 10 Mar 2018
Hello, everyone. Is there a way (function) in Matlab to rotate a row vector of N dimensions by a given angle? I've only been able to use the matrix multiplication for 2D and 3D cases.
Thanks!
  5 commentaires
Peter Popoola
Peter Popoola le 10 Mar 2018
Thanks for the comment, Guillaume. I didn't know that. I guess I'll have to find a way around it.
Jan
Jan le 10 Mar 2018
I consider this as not complicated:
R = eye(numel(u)) + ...
(v * u.' - u * v.') * sin(a) + ...
(u * u.' + v * v.') * (cos(a) - 1);
Here u and v are two orthogonal unit vectors to describe the n-dimensional hyperplane to rotate in. Remember, that in 3D one vector is sufficient to define a plane to rotate in, but in 4D (and N-D), this is not unique anymore. a is the angle in radians to rotate, and the direction is from u to v.
I publish this in the FileExchange currently.

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Réponses (2)

Rik
Rik le 8 Mar 2018
You mean something like this?
v=1:10;
v2=imrotate(v,45);
  5 commentaires
Rik
Rik le 10 Mar 2018
File a bug report with GNU. There are often minor differences between Octave and Matlab, especially in edge cases like this. Apparently Octave assumes both dimensions are larger than 1.
Peter Popoola
Peter Popoola le 10 Mar 2018
Okay, Rik. Thank you!

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Jan
Jan le 8 Mar 2018
Modifié(e) : Jan le 10 Mar 2018
Here the axis of rotation u, the cross-product matrix []_x and the tensor cross-product (x) are not limited to 3D, but work for n dimensions also. So you can create the n-D rotation matrix in a straight-forward way and multiply your vector with.
  2 commentaires
Peter Popoola
Peter Popoola le 9 Mar 2018
Thanks once again, Jan. I take it there's no Matlab function that does this? Because I haven't really been able to wrap my head around the formulation given here, and how it can be extended to the N-dimensional case. Thank you for your help!
Jan
Jan le 10 Mar 2018

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