Effacer les filtres
Effacer les filtres

Array indexing for moving IQR

2 vues (au cours des 30 derniers jours)
Anna McCann
Anna McCann le 11 Mar 2018
I'm calculating a moving iqr, similar to the movmean, movmad, and movstd functions, discarding the endpoints:
A = [4 8 6 -1 -2 -3 -1 3 4 5];
for i = 1:length(A)-k+1
M(i) = iqr(A(i:i+k-1)
end
M = [3.0000 6.7500 6.0000 1.5000 1.5000 4.5000 3.7500 1.5000]
M is as expected. How can I do this more efficiently using array indexing?

Réponses (2)

Jos (10584)
Jos (10584) le 12 Mar 2018
When N (= number of elements in A) and K (= number of elements to use) are not too large you could create an intermediate (N-K+1)-by-K array. This could be (slightly) more efficient than a for-loop but also looks more cryptic ...
A = [4 8 6 -1 -2 -3 -1 3 4 5]
K = 3
N = numel(A)-K+1
I = cumsum([1:N ; ones(K-1,N)], 1)
M = iqr(A(I), 1)
  1 commentaire
Anna McCann
Anna McCann le 12 Mar 2018
Okay thanks, I'll try profiling it and see if it speeds it up.

Connectez-vous pour commenter.


Walter Roberson
Walter Roberson le 12 Mar 2018
R2016b and later,
iqr(A((1:k).'+(0:length(A)-k)))

Catégories

En savoir plus sur Matrices and Arrays dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by