Hi everybody. I wrote a code but something is going wrong, I need at that point.
I need to stop the code at the gain of 0.5 and I need to take the values that I need as P and D. But The code does not do what I need. It always work around i = 65 and j = 65. What is the error ?
clear all; clc;
Kp = -10:0.31:10;
Kd = -10:0.31:10;
% n = [Kd Kp];
% d = [(1+Kd) (Kp+1)];
%
% [r,p,k] = residue(n,d);
A = zeros(length(Kp), length(Kd));
for i = 1:length(Kp)
for j = 1:length(Kd)
n = [Kd(j) Kp(i)];
d = [(1+Kd(j)) (Kp(i)+1)];
[r,p,k] = residue(n,d);
S = sum(r);
TF = tf(n,d);
[z, gain] = zero(TF);
if gain == 0.5
break;
end
% if S<0.6 && S>0.4
% A(i,j) = 1;
% else
% A(i,j) = 0;
% end
end
end

Réponses (1)

James Tursa
James Tursa le 20 Mar 2018

0 votes

It is often better to use tolerances for floating point comparisons, unless you wrote the underlying code and you know that the result must be exactly 0.5. So this test
if gain == 0.5
should probably look something like this instead
if abs(gain - 0.5) < tol % for some appropriate value of tol

5 commentaires

Stephen23
Stephen23 le 21 Mar 2018
Modifié(e) : Stephen23 le 21 Mar 2018
Berkcan Oz's "Answer" moved here:
What do you mean ? What should I change ?
Stephen23
Stephen23 le 21 Mar 2018
Modifié(e) : Stephen23 le 21 Mar 2018
@Berkcan Oz: your code contains exactly one instance of the operator ==. Change it as James Tursa recommended.
Berkcan Oz
Berkcan Oz le 21 Mar 2018
What is tol ? How to define ?
Stephen23
Stephen23 le 21 Mar 2018
You could start with tol=1e-5;
Berkcan Oz
Berkcan Oz le 21 Mar 2018
Modifié(e) : Walter Roberson le 21 Mar 2018
Now, I did this but this give me a system that starts at gain almost 0.5 and goes 1. I need to make it from 0 to 0.5. Not from 0.5 to 1. What should I do ?
clear all; clc;
Kp = -10:0.31:10;
Kd = -10:0.31:10;
tol = 1e-5;
A = zeros(length(Kp), length(Kd));
for i = 1:length(Kp)
for j = 1:length(Kd)
n = [Kd(j) Kp(i)];
d = [(1+Kd(j)) (Kp(i)+1)];
[r,p,k] = residue(n,d);
S = sum(r);
TF = tf(n,d);
[z, gain] = zero(TF);
if gain <0.6 && gain>0.4
break;
end
end
end
sys = tf(n,d)
step(sys);
grid;

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