How to solve system of coupled second order linear differential equations in Matlab?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
theta'' + 13.7786 x''+ (theta')^2=0;
-theta'' + 13.7786 y'' + (theta')^2=0;
0.5 theta''- x''(cos(theta))+y''(sin(theta))=0.24sin(theta);
1st Order and second order seperable equations are easy to solve, but in this case i don't know how can i solve it in Matlab.
- x =f1
- y =f2
- theta =f3
- x_dot =f4
- y_dot =f5
- theta_dot =f6
- x_dotdot =-(f6+diff(f6))/(13.7786)
- y_dotdot
- theta_dotdot
the problem is as you can see diff(f6) in x_dotdot, is it okay?
1 commentaire
Roger Stafford
le 30 Mar 2018
Your equations are linear with respect to all three second derivatives. Therefore, you can "solve" them as far as these second derivatives are concerned, obtaining something of the form:
theta'' = some expression involving theta' and theta
x'' = another expression involving theta' and theta
y'' = yet another expression involving theta' and theta
These results are all you need to call upon one of Matlab's 'ode' functions.
Réponses (1)
Abraham Boayue
le 29 Mar 2018
I would recommend that you post your equations as an attachment. Problems of this form are usually not clear when written as a code.
0 commentaires
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!