a simple evoulutionary algorithm 1. the user can enter any user defined string as the evolutionary tareget up to 30 characters max
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
yared Zeleke
le 30 Mar 2018
Commenté : yared Zeleke
le 31 Mar 2018
clc
clear
t= 'Hell world!';
numRands=length(t);
tlength=numRands;
source=t(ceil(rand(1,tlength)*numRands));
fitval = fitness(source, t);
i = 0;
while 1
i = i + 1;
m = mutate(source);
fitval_m = fitness(m, t);
if fitval_m < fitval
fitval = fitval_m;
source = m;
fprintf('%5i %5i %14s', i, fitval_m, m);
end
if fitval == 0
break
end
end
function fitval = fitness(source, t)
fitval = 0
for i = 1 : length(source)
fitval = fitval + (double(t(i)) - double(source(i))) ^ 2;
end
end
function parts = mutate(source)
parts = source;
charpos = randi(length(source)) - 1;
parts(charpos) = char(double(parts(charpos)) + (randi(3)-2));
end
2 commentaires
Réponse acceptée
Walter Roberson
le 31 Mar 2018
You have
charpos = randi(length(source)) - 1;
The result of that can be 0 because randi might have generated a 1. You then have
parts(charpos) = char(double(parts(charpos)) + (randi(3)-2));
but charpos can be 0 so you can be attempting to index at location 0, which is not defined.
I do not know why you are subtracting 1 at the point?
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur MATLAB Coder dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!