Why am I getting Inf in my matrix

I am trying to divide each position element by element, and every time the denominator = 0 I want to set the result to 1 so I don't get any infinity values (for dividing by zero). When I run the code and test with find(isinf(g)) there are a ton of values that come up as infinity. Can anyone explain why?

clc
close all

x = [0 0 0; 1 2 3;0 2 4];
y = [1 2 0; 2 4 6; 2 4 5];

for u=1:3
    for v=1:3
        if (x(u,v) == 0)
            g(u,v) = 1;
        else
            g(u,v) =y(u,v)/x(u,v);
        end
    end
end

Answer 1

[Roger Stafford]

It is easily possible for two finite nonzero numbers to have a quotient so large that Matlab must give 'inf' as its value. For example

x = 0.01*realmax;
y = 0.0001;
q = x/y;  % <-- This will yield inf for q

I suggest you make a study of the corresponding x and y values that give rise to your inf values to see what kinds of number pairs are involved.

[paul lestingi]

I'm not sure I understand. There are only two 3x3 matricies being evaluated and by looking at them none of the quotients should be near infinity.