hello , i want to remove the repeated values in vector without using Unique function
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if a = [1 1 2 2 3 3 1] i want the result to be a=[1 2 3] thanks
Réponses (2)
Birdman
le 1 Avr 2018
A = [1 1 2 2 3 3 1]
[val,idx]=sort(A)
idx=A(idx(1:end-1))==A(idx(2:end))
val(idx)=[] % take it as new A vector
4 commentaires
Ashraf Hisham
le 1 Avr 2018
Birdman
le 1 Avr 2018
Do not need to. My way is more efficient. Try it.
Ashraf Hisham
le 1 Avr 2018
Walter Roberson
le 1 Avr 2018
Okay, suppose you are examining element 4 out of 7, and you need to delete it because it is the same as something earlier. So you x(4)=[] . Now x is length 6. But your for loop still goes to 7.
You need to use one of these techniques:
- keep a record of which items are to be deleted and delete them all at the same time after you have done your loops; or
- start at the end and move to the beginning so that when the array gets shorter that does not matter because you are only going to look at earlier elements. (You might need to adjust this strategy for your situation.)
Walter Roberson
le 1 Avr 2018
find(sparse(a,ones(size(a)),1))
Note: only works for positive integers.
1 commentaire
Ashraf Hisham
le 1 Avr 2018
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