- you want each element in Frequency (40k elements) to be changed to somewhere between 90% and 110% of it's current value.
- you want a uniform distribution, not say normally distributed noise.
10% random noise to an array of values
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How do I add 10 % random noise to freq = 1:40e3
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William Smith
le 3 Avr 2018
Not totally clear what you want, but let's assume
Then:
multiplier = 0.9 + rand(size(freq)) * 0.2;
answer = freq .* multiplier;
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Muhammad Tauha Ali
le 30 Août 2021
the reason for above equation is explained here: http://ocw.uci.edu/upload/files/mae10_w2011_lecture13.pdf
1.1-0.9=0.2 meaning +-10% noise.
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