Definit integral within a larger equation for a root mean square calculation

I am struggling to apply the correct code to evaluate an equation with an integral included. File attached. Any pointers gratefully received.

4 commentaires

Torsten
Torsten le 4 Avr 2018
Modifié(e) : Torsten le 4 Avr 2018
The right-hand side does not depend on t. Thus V3rms(t) cannot be correct.
Further: How is Y(t) given ? As a list of pairs (t_i,Y(t_i)) ?
Thank you Torsten. The formula is a standard one used to calculate the root mean square value of a varying voltage (Y) as a function of t. The root part is given by the sqrt, the mean is given by the period t2 - t1. I have used this formula many times in Mathcad but I am missing something in the Matlab code protocols.
Kind Regards
The formula that I pasted in to the question is misleading, for which I apologise. I copied it directly from Mathcad but V3rms is expressed as a function of t (V3rms(t)) only so that I could plot V3rms against time. So the formula is corrct but it should just read (V3rms = etc.
Sorry.
Torsten
Torsten le 5 Avr 2018
Modifié(e) : Torsten le 5 Avr 2018
And how is Y(t) given ? As an explicit function ? As a list of pairs (t_i,Y(t_i)) ?

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 Réponse acceptée

Torsten
Torsten le 5 Avr 2018
Modifié(e) : Torsten le 5 Avr 2018
t0 = 0;
t1 = 0.01;
f = 1.0/0.02;
Vrms = sqrt(1/(t1-t0)*integral(@(t)sin(2*pi*t*f).^2,t0,t1))
Best wishes
Torsten.

Plus de réponses (2)

Good morning Torsten, Y is the sum of two sinusoidal voltages sampled over a period of 10 milliseconds (t2 = 10ms and t1 = 0ms). One sinusoidal voltage is at the fundamental frequency of 50 hz and the other at the third harmonic of 150 hz. Attached is an extract from a Mathcad calculation.
Kind Regards
Dear Torsten,
Thank you. I now understand the problem.
Kind Regards

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