Plotting contour lines at specific value

I have two functions f1 and f2 defined as follows:
f1(x) = x_1^2 + x_2^2 - 4
f2(x) = 5(x_1 - 1)^2 - x_2 - 3
where x = (x_1,x_2)^T.
Now I want to plot the contour lines of these functions at value 0, that is, I want to plot the functions
x_1^2 + x_2^2 - 4 = 0
5(x_1 - 1)^2 - x_2 - 3 = 0
I tried using contourplot, but no luck there. Is there a smarter way, for example using Linspace?

 Réponse acceptée

Matt Fig
Matt Fig le 24 Mar 2011
Please re-paste your code and use the code format button so we can read it. I see a bunch of ? marks in the code.
When using the CONTOUR function, you can provide an argument which tells the function where to draw the contours.
Here is a way to get a surface and contours in one plot:
[x_1,x_2] = meshgrid(-10:.1:10,-10:.1:10);
f1 = @(x_1,x_2) x_1.^2 + x_2.^2 - 4;
f2 = @(x_1,x_2) 5*(x_1 - 1).^2 - x_2 - 3;
subplot(2,1,1)
surfc(x_1,x_2,f1(x_1,x_2))
subplot(2,1,2)
surfc(x_1,x_2,f2(x_1,x_2))
To get just the surface, use the SURF function.

6 commentaires

David
David le 24 Mar 2011
I can only see contour(X,Y,Z,n), where n is the number of lines, not there specific z-value.
Matt Fig
Matt Fig le 24 Mar 2011
From the documentation:
CONTOUR(Z,V) and CONTOUR(X,Y,Z,V) draw LENGTH(V) contour lines
at the values specified in vector V. Use CONTOUR(Z,[v v]) or
CONTOUR(X,Y,Z,[v v]) to compute a single contour at the level v.
David
David le 24 Mar 2011
I have no idea how I missed that option. Is there a simpler way to do this, if for example if I just wanted to plot the curve
x_1^2 + x_2^2 - 4 = 0
Is it possible to plot the curve, without using contourplot?
Matt Fig
Matt Fig le 24 Mar 2011
See my answer above.
Mohammad Sohail
Mohammad Sohail le 30 Mai 2017
@David try this
syms x y
ezplot(x^2+y^2-4)
Avinash Kumar
Avinash Kumar le 9 Avr 2019
thanks

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kanekal kullayappa
kanekal kullayappa le 24 Fév 2014

0 votes

hello sir, I need the function to obtain the plots in the joint tdoa and aoa location algorithm http://www.jseepub.com/EN/article/downloadArticleFile.do?attachType=PDF&id=11834.

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