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How to solve the equation?
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I have the following code to do fft();
d='cameraman.png';
F=fft2(d);
Fsh=fftshift(F);
s2=log(1+abs(Fsh));
In the fourth step, I wanted to get the value of Fsh, What should be the format to find this in matlab.
I tried doing this operation:
Fsh=round(exp(s2))-1
Can somebody help me with the right format to do this equation in matlab?
2 commentaires
Walter Roberson
le 16 Avr 2018
You cannot take the fft of a character string.
Have you considered reading in the file named by the character string?
Shounak Shastri
le 16 Avr 2018
Use 'imread()'to read the file.
But if you want to find the fft of the string, then convert it to integer or double before taking the fft.
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