extract data un 2D array to create 3d array
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alice dormeuil
le 16 Avr 2018
Réponse apportée : alice dormeuil
le 20 Avr 2018
Hello,
I'm new on Matlab, and I would like to create a 3D array by extracting data in a 2D array.
I Have an array, containing eye data during multiple Trials, which size is 6942173x1cell (the attached file is smaller in order to attached it). Each trial start with 'MSG Number... Recenter Cue Event'. I would like to extract data of each trial and to create a 3D array containing each trial data in different pages.
I created this code but the loop doesn't work, it extracts only the first trial and doesn't create a 3D array.
idx1 = find(~cellfun('isempty',strfind(Edf,'Recenter Cue Event')));
for i=1:1:size(Edf)
for k=1:size(idx1)
if i==idx1(k)
Edf_Trials(:,:,k)=Edf(idx1(k):idx1(k+1)-1);
else
i=i+1;
end
end
end
Thank you for your help
Alice
9 commentaires
Bob Thompson
le 18 Avr 2018
I'm assuming the error message occurs on this line:
Edf_Trials(:,:,k)=Edf(idx1(k):idx1(k+1)-1);
If so, then it is most likely because you can't have k+1 when k=size(idx1). I would suggest writing an if statement that looks for this condition and just tells the Edf range to go to the end. This can be part of your current if statement, but the condition needs to come before what you have now.
if k == size(idx1,1)
...
elseif i == idx1(k)
...
end
Also, I would suggest it is good coding practice to specify a single dimension when using size() or to use two variables as outputs.
[row, col] = size(idx1);
By making those two changes your code seemed to run fine for me with a bunch of dummy data. This makes me think that the bug is in the recognition of 'Recenter Cue Event'. What is the value of idx1 when you run it? (I know you included a sample of your data, and thank you, but for personal paranoia reasons I don't download things off this site.)
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