I am getting an error "Undefined function or variable 'Dictionary'".
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I have used switch case in my function such that for training (part1 ) case 1 will be executed and for testing (part 2) case 2 will be executed. However, the variable Dictionary created in case 1 will be used to case 2 also. The function which I have wrote is
1 commentaire
Walter Roberson
le 30 Avr 2018
Please do not close questions that have an answer
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KALYAN ACHARJYA
le 19 Avr 2018
Modifié(e) : KALYAN ACHARJYA
le 19 Avr 2018
%What I understood: Your code Case 1: Switch statement; dictionary variable; Case2: execute; %Gives error >>Suggested Modification as follows Case 1: dictionary variable; Switch statement; Case2: execute;
2 commentaires
KALYAN ACHARJYA
le 19 Avr 2018
Modifié(e) : KALYAN ACHARJYA
le 19 Avr 2018
Previously you accepted the answer. I hope your question is answered Pls share your code. Above is not exact code, just way steps how you should follow.
KALYAN ACHARJYA
le 19 Avr 2018
Modifié(e) : KALYAN ACHARJYA
le 20 Nov 2019
Change the name of variable, avoid case as variable variable.
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