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I am getting an error "Undefined function or variable 'Dictionary'".

13 vues (au cours des 30 derniers jours)
kitty varghese
kitty varghese le 19 Avr 2018
I have used switch case in my function such that for training (part1 ) case 1 will be executed and for testing (part 2) case 2 will be executed. However, the variable Dictionary created in case 1 will be used to case 2 also. The function which I have wrote is

Réponses (1)

KALYAN ACHARJYA
KALYAN ACHARJYA le 19 Avr 2018
Modifié(e) : KALYAN ACHARJYA le 19 Avr 2018
 %What I understood: Your code
Case 1:
Switch statement;
dictionary variable;
Case2:
execute;
%Gives error
>>Suggested Modification as follows
Case 1:
dictionary variable; 
Switch statement;
Case2:
execute;
  2 commentaires
KALYAN ACHARJYA
KALYAN ACHARJYA le 19 Avr 2018
Modifié(e) : KALYAN ACHARJYA le 19 Avr 2018
Previously you accepted the answer. I hope your question is answered Pls share your code. Above is not exact code, just way steps how you should follow.
KALYAN ACHARJYA
KALYAN ACHARJYA le 19 Avr 2018
Modifié(e) : KALYAN ACHARJYA le 20 Nov 2019
Change the name of variable, avoid case as variable variable.

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