How to find all possible routes with a given node matrix?
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Jung Sunghun
le 25 Avr 2018
Commenté : Jung Sunghun
le 20 Oct 2018
Hello,
I am trying to write a function to find all possible routes from the Start node, 6, to the Goal node, 21, with the given node matrix, A, as shown in the below.
A =
1 6
1 23
2 3
2 4
2 5
3 2
4 2
4 7
5 2
5 11
6 1
6 26
7 4
7 8
8 7
8 9
8 24
9 8
9 23
10 11
10 13
10 15
10 16
11 5
11 10
12 13
12 14
13 10
13 12
13 24
14 12
14 19
15 10
15 17
16 10
16 17
16 18
17 15
17 16
17 25
18 16
18 19
18 22
19 14
19 18
19 20
20 19
21 22
21 27
22 18
22 21
22 25
23 1
23 9
24 8
24 13
25 17
25 22
26 6
27 21
I would like to build a function which results the following outputs.
[6,1,23,9,8,7,4,2,5,11,10,15,17,25,22,21]
[6,1,23,9,8,7,4,2,5,11,10,15,17,16,18,22,21]
[6,1,23,9,8,7,4,2,5,11,10,16,17,25,22,21]
[6,1,23,9,8,7,4,2,5,11,10,16,18,22,21]
[6,1,23,9,8,24,13,10,15,17,25,22,21]
[6,1,23,9,8,24,13,10,16,17,25,22,21]
[6,1,23,9,8,24,13,10,16,18,22,21]
[6,1,23,9,8,24,13,12,14,19,18,16,10,15,17,25,22,21]
[6,1,23,9,8,24,13,12,14,19,18,16,17,25,22,21]
[6,1,23,9,8,24,13,12,14,19,18,22,21]
Thank you very much for your invaluable time to help on this problem.
Best regards,
Sunghun Jung
3 commentaires
Walter Roberson
le 15 Oct 2018
You effectively have an undirected graph. There are an infinite number of routes unless you add constraints.
Réponse acceptée
Bruno Luong
le 15 Oct 2018
Modifié(e) : Bruno Luong
le 15 Oct 2018
I found actually 13 paths, more than the 10 you have listed:
[6 1 23 9 8 7 4 2 5 11 10 13 12 14 19 18 16 17 25 22 21]
[6 1 23 9 8 7 4 2 5 11 10 13 12 14 19 18 22 21]
[6 1 23 9 8 7 4 2 5 11 10 15 17 16 18 22 21]
[6 1 23 9 8 7 4 2 5 11 10 15 17 25 22 21]
[6 1 23 9 8 7 4 2 5 11 10 16 17 25 22 21]
[6 1 23 9 8 7 4 2 5 11 10 16 18 22 21]
[6 1 23 9 8 24 13 10 15 17 16 18 22 21]
[6 1 23 9 8 24 13 10 15 17 25 22 21]
[6 1 23 9 8 24 13 10 16 17 25 22 21]
[6 1 23 9 8 24 13 10 16 18 22 21]
[6 1 23 9 8 24 13 12 14 19 18 16 10 15 17 25 22 21]
[6 1 23 9 8 24 13 12 14 19 18 16 17 25 22 21]
[6 1 23 9 8 24 13 12 14 19 18 22 21]
Test code:
A =[ 1 6
1 23
2 3
2 4
2 5
3 2
4 2
4 7
5 2
5 11
6 1
6 26
7 4
7 8
8 7
8 9
8 24
9 8
9 23
10 11
10 13
10 15
10 16
11 5
11 10
12 13
12 14
13 10
13 12
13 24
14 12
14 19
15 10
15 17
16 10
16 17
16 18
17 15
17 16
17 25
18 16
18 19
18 22
19 14
19 18
19 20
20 19
21 22
21 27
22 18
22 21
22 25
23 1
23 9
24 8
24 13
25 17
25 22
26 6
27 21];
p = gallpaths(A,6,21);
for k=1:length(p)
fprintf('%s\n', mat2str(p{k}));
end
Using this function GALLPATHS I made
function p = gallpaths(A,start,last)
% find all direct paths from start to last
% A is (n x 2) each row is an edges
A = sortrows(A);
b = true(size(A,1),1);
p = gapengine(A,b,start,last);
end
function p = gapengine(A,b,start,last)
% recursive engine
if start==last
p = {last};
else
bs = A(:,1) == start;
next = A(bs & b,2);
p = {};
b(bs) = false;
for k=1:length(next)
i = next(k);
pk = gapengine(A,b,i,last);
pk = cellfun(@(p) [start, p], pk, 'unif', 0);
p = [p, pk];
end
end
end
3 commentaires
Bruno Luong
le 15 Oct 2018
Nope find all paths has exponential complexity. AFAIK this is intrinsic to the problem you want to solve rather than the algorithm.
Plus de réponses (1)
Walter Roberson
le 15 Oct 2018
2 commentaires
Walter Roberson
le 19 Oct 2018
See also https://www.geeksforgeeks.org/find-paths-given-source-destination/ which gives code in C, Java, and Python.
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