Split variable length vector by parts

So it's probably an easy solution, but can't really find the answer that quick.
I have the following vector:
V = [1 2 3 4 5 ... n];
P = ceil(length(V/127)); %dont know if ceil or floor is better
And then I want to split the vector `V` in parts `P`, so that I'll get something like the following:
% as an example n = 2184 & P = 17
C = {[1 2 3 ... 18],[18 19 20 ... 35],...[2167 2168 2169 ...2184]};
Thanks in advance

1 commentaire

Ameer Hamza
Ameer Hamza le 25 Avr 2018
Modifié(e) : Ameer Hamza le 25 Avr 2018
You mentioned that P=17 but your first element of C contain 18 elements. What to do, if elements of V can't be divided properly, e.g. 2184/17 is not an integer. How do you want to handle it?

Connectez-vous pour commenter.

 Réponse acceptée

dpb
dpb le 25 Avr 2018
L-length(V);
P=17;
id2=[repmat(P,1,fix(L/P)) rem(L,P)]; % number elements in cell size P matching L plus remainder
C=mat2cell(V,1,id2);
That's for the nearest multiple of P with whatever is left over tacked onto the end irregardless of its size relative to P. If it's needed to make as near even as possible need more logic to choose the bin size; that's not a given criterion in the question posed, however.

1 commentaire

YT
YT le 25 Avr 2018
Modifié(e) : YT le 25 Avr 2018
While it works fine and I accepted your answer, I've created a new question related to this one (for more logical sizes of subvectors) >here<

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

Question posée :

YT
le 25 Avr 2018

Modifié(e) :

YT
le 25 Avr 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by