Effacer les filtres
Effacer les filtres

Fitting a plane through a 3D point data

15 vues (au cours des 30 derniers jours)
ha ha
ha ha le 6 Mai 2018
Modifié(e) : Matt J le 6 Mai 2018
For example, i have 3d point cloud data [xi, yi, zi] as the attachment .txt file. I want to fit a plane to a set of 3D point data. What kind of method to do that?
  1 commentaire
Matt J
Matt J le 6 Mai 2018
How does one know that M and L are different planes and not just noise? Is there a known upper bound on the noise? A known lower bound on the separation distance between M and L?

Connectez-vous pour commenter.

Réponse acceptée

Matt J
Matt J le 6 Mai 2018
You will probably have to implement a RANSAC plane fitting routine.
  5 commentaires
ha ha
ha ha le 6 Mai 2018
Thanks.
Matt J
Matt J le 6 Mai 2018
Modifié(e) : Matt J le 6 Mai 2018
One approach you might consider is to take planar cross sections of your data. This will give 2D data for a line, with outliers. Then you can apply a ready-made RANSAC line-fitter, like the one I linked you to. From line fits in two or more cross-secting planes you should be able to construct the desired plane K.

Connectez-vous pour commenter.

Plus de réponses (2)

Walter Roberson
Walter Roberson le 6 Mai 2018
data = load('1.txt');
coeffs = [data(:,1:2), ones(size(data,1),1)]\data(:,3);
The equation of the plane is then coeffs(1)*x + coeffs(2)*y - coeffs(3) = z
  1 commentaire
ha ha
ha ha le 6 Mai 2018
Modifié(e) : ha ha le 6 Mai 2018
From your answer, I plot the surface as below image. But That plane is not same as my expected plane. If we use the formulas as your proposed method, the plane is fitting through all points & will be slightly different with my expected plane K(=plane M)

Connectez-vous pour commenter.


Matt J
Matt J le 6 Mai 2018
Modifié(e) : Matt J le 6 Mai 2018
xyz=load('1.txt');
xyz(xyz(:,2)>40, :)=[];
mu=mean(xyz,1);
[~,~,V]=svd(xyz-mu,0);
normal=V(:,end).';
d=normal*mu';
The equation of the plane is then xyz*normal.' = d
  3 commentaires
ha ha
ha ha le 6 Mai 2018
In my question: Plane M contains a large number of point data when compared with plane L(i.e., 90%). I wanna find the plane can cover large number points as plane M. Example: in the general, there are some outlier(or noise) points. So, the result will be affected significantly. Because you are using "least square regression method" as I guessed
Matt J
Matt J le 6 Mai 2018
How does one know that M and L are different planes and not just noise? Is there a known upper bound on the noise? A known lower bound on the separation distance between M and L?

Connectez-vous pour commenter.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by