How do I store result from a loop into matrix?
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I have 360 signals to be processed and I'm using STFT for my project. The result for one signal returns:
S = 33x147 double
How do I take only the first column from every 360 signals processed and store it in the same matrix? And how do I make a loop to make it do the same thing but advance to the next column up to the 147th column until I've 147 different matrices of result S?
Thank you in advance.
2 commentaires
Ameer Hamza
le 6 Mai 2018
Does your result require 147 matrices at the end? Like this
Result{1} = [first columns of S for all 360 signals] = 33 x 360 matrix
Result{2} = [second columns of S for all 360 signals] = 33 x 360 matrix
....
Result{147} = [147th columns of S for all 360 signals] = 33 x 360 matrix
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Wick
le 6 Mai 2018
Modifié(e) : Wick
le 6 Mai 2018
The first column of S can be indexed S(:,1). The nth is S(:,n);
Instead of making 360 different matrices with different names, we're going to make a three-dimensional array, A, with 360 different pages.
clearvars
num_rows = 33;
num_signals = 360;
num_pages = 147;
A = zeros(num_results, num_signals, num_pages);
for jj = 1:num_signals
% replace the following line with your calculation of S
S = rand(num_results,num_pages);
A(:,jj,:) = reshape(S,num_results,1,num_pages);
end
Each page of A (the different columns from your values of S pasted together into a matrix) can be indexed as:
page_of_columns = A(:,:,n)
where 'n' is the column id you want (from 1 to 147 in your example)
7 commentaires
Wick
le 6 Mai 2018
Modifié(e) : Wick
le 6 Mai 2018
clearvars
num_rows = 33;
num_signals = 360;
num_pages = 147;
num_results = 1;
A = zeros(num_results, num_signals, num_pages);
% load a .mat file
load ('Defect_Signals_with_Labels.mat');
for jj = 1:num_signals
x = Signals_Combined(:,jj);
.....
S = 20*log10(S + 1e-6);
A(:,jj,:) = reshape(S,num_results,1,num_pages);
end
The assumption is that 'S' is different each time based on whatever is above it inside the loop.
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