how do i use different parts of a variable for the same code?

I have this code in which i have to calculate the Gn variable shown below for two different iterations. In each iteration the value of D(a matrix) changes. My question is how do i make it that for the first iteration the variables dn,dtx,dty,dtz and d0n use only the four numbers of m0 as it is now but for the second iteration it uses the last four numbers of m0.

    outd0 = cell(2,1);
    outGt = cell(1,2);
    for iter=1:2
        m0=[0; 0; 0; 0; 0 ;0 ;0 ;0];
        sG=stationGroups{iter};
        n=length(sG);
        rowVector=ones(1,n);
        dt0=rowVector;
        D=sG';
        dn=sqrt((D(1,:)-m0(2)).^2+(D(2,:)-m0(3)).^2+(D(3,:)-m0(4)).^2);
        dtx = -(D(1,:)-m0(2))./(v.*dn);
        dty = -(D(2,:)-m0(3))./(v.*dn);
        dtz = -(D(3,:)-m0(4))./(v.*dn);
        Gn=[dt0; dtx; dty; dtz];
        Gt=Gn';
        outGt{iter} = Gt;
        Gt1=cell2mat(outGt(1,1));
        Gt2=cell2mat(outGt(1,2));
        G=blkdiag(Gt1,Gt2);
        d0n=(m0(1)+(vecnorm(repmat(m0(2:4),1,n)-D(:,1:n)))./v);
        d0t=d0n';
        outd0{iter} = d0t;
        d01=cell2mat(outd0(1,1));
        d02=cell2mat(outd0(2,1));
        d0=[d01;d02];
    end

Answer 1

[Image Analyst]

Use an if statement

if iter == 1
    dn=sqrt((D(1,:)-m0(2)).^2+(D(2,:)-m0(3)).^2+(D(3,:)-m0(4)).^2);
    dtx = -(D(1,:)-m0(2))./(v.*dn);
    dty = -(D(2,:)-m0(3))./(v.*dn);
    dtz = -(D(3,:)-m0(4))./(v.*dn);
else
    dn=sqrt((D(1,:)-m0(6)).^2+(D(2,:)-m0(7)).^2+(D(3,:)-m0(8)).^2);
    dtx = -(D(1,:)-m0(6))./(v.*dn);
    dty = -(D(2,:)-m0(7))./(v.*dn);
    dtz = -(D(3,:)-m0(8))./(v.*dn);
end

However note that you set m0 to all zeros on every iteration so I don't see why you're even wanting to use it.

[Feliciano Döring]

Yeah i put it wrong the m0 is supposed to be outside the loop, thanks!

Answer 2

[Fangjun Jiang]

m0=[1 2 3 4; 10 20 30 40];
for iter=1:2
    m0(iter,1)
    m0(iter,2)
end

[Feliciano Döring]

But then m0 isn't a column vector, i need it to be a column vector