How does OR work in an IF statement?
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I want the IF statement to check the value of 'Highest_value_month' and give 'Days' a value based on that, yet 'Days' always gets the value 31. As far as I know the syntax for OR is '||'. So why doesn't my IF statement work?
Highest_value_month = 6;
if Highest_value_month == 1 || 3 || 5 || 7 || 8 || 10 || 12
Days = 31;
elseif Highest_value_month == 2
Days = 28;
else
Days = 30;
end
The code is simplified in this case but it is essentially the same.
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Rik
le 11 Mai 2018
Because each is treated as separate test. Therefor you will need to use something like the line below. You could also use switch and case (see second example).
if Highest_value_month == 1 || ...
Highest_value_month == 3 || ...
Highest_value_month == 5 || ...
Highest_value_month == 7 || ...
Highest_value_month == 8 || ...
Highest_value_month == 10 || ...
Highest_value_month == 12
Days = 31;
end
or with switch:
switch Highest_value_month
case {1,3,5,7,8,10,12}
Days = 31;
case 2
Days = 28;
otherwise
Days = 30;
end
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KSSV
le 11 Mai 2018
Modifié(e) : KSSV
le 11 Mai 2018
Highest_value_month = 6;
val = [1 3 5 7 8 10 12] ;
if intersect(Highest_value_month,val)
Days = 31;
elseif Highest_value_month == 2
Days = 28;
else
Days = 30;
end
OR
Highest_value_month = 12;
val = [1 3 5 7 8 10 12] ;
if ismember(Highest_value_month,val)
Days = 31;
elseif Highest_value_month == 2
Days = 28;
else
Days = 30;
end
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