Lay one vector onto another

Say you had two row vector:

filter = [0 0 0 0 0 0 0 0 0 0 ];
values = [1 2 1];

And the goal is to "lay the vector values onto the vector filter" like this:

new_filter = [0 0 1 2 1 0 0 0 0 0];

Here being done onward from index 3, or any other index.

How would that work?

[Stephen23]

"Here being done onward from index 3, or any other index. How would that work?"

You said it yourself: using indexing. What have you tried so far?

[Joschua Kraus]

This works:

filter + [zeros(1,index-1) vals zeros(1,length(filter)-(index-1)-length(vals))]

thought there might be a build-in function

Answer 1

[Cathal Cunningham]

One method would be a for loop

filter = [0 0 0 0 0 0 0 0 0 0 ];
values = [1 2 1];
startIdx = 3;
for i = startIdx:length(filter)-startIdx+1
new_filter = filter;
new_filter(i:i+length(values)-1) = values
end

Or you could try circshift

filter = [0 0 0 0 0 0 0 0 0 0];
values = [1 2 1];
startIdx = 3;
new_filter = filter;
new_filter(startIdx:startIdx+length(values)-1) = values
for i = 1:length(filter)
    new_filter = circshift(new_filter,1)
end