Why isn't my loop working?

2 vues (au cours des 30 derniers jours)
Madison Goodwin
Madison Goodwin le 18 Mai 2018
Commenté : Madison Goodwin le 18 Mai 2018
fid = uigetfile('*.*');
fid = fopen(fid);
deltat = 0.5;
n = 1;
while fgetl(fid)~= -1
line = fgetl(fid);
line = sscanf(line, '%f V, %i counts, %i ms');
vout = line(1);
counts = line(2);
t = line(3)/1000;
t(n+1) = t(n) + deltat;
% Q = flowrate (L/s)
% h = head(m)
% P = pressure
% p = density of water
p = 1000; %kg/m^3);
g = 9.81;
vs = 5;
% vout - get from data
% h - get from data
% Q - calculated from data
P = ((vout/vs) - 0.04)/0.0018;
% Finding head
h = (P/1000)/(p*g);
Q = counts/((t(n)/1000)*330);
% Finding hydraulic power
H =(Q*p*g*h)/1000;
end
  6 commentaires
Madison Goodwin
Madison Goodwin le 18 Mai 2018
Ok now it is producing all the values, but the time step is not updating as I would like it, it is meant to increase by 0.5 seconds for each line, but for each line in the data the t value is 0.5.
Madison Goodwin
Madison Goodwin le 18 Mai 2018
So if I have these two lines as my code will it update the timestep, the value of line(3) is 500ms. After dividing by 1000 it is 0.5, and deltat is 0.5
t = line(3)/1000;
t = t + deltat;

Connectez-vous pour commenter.

Réponses (1)

Greg
Greg le 18 Mai 2018
Modifié(e) : Greg le 18 Mai 2018
Purely a guess, you goofed up some indexing:
t = line(3)/1000; % <-- Recreates a new "t" as a scalar every loop iteration
t(n+1) = t(n) + deltat; % <-- Therefore, t(n) does not exist, or is 0
Also, I don't see you incrementing n anywhere.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by