- avoids the problem with "greedies"
- better performance; easier to evaluate
Help using Regexp:
14 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello,
I'm a bit confused on how to use regexp to get information that's between braces. For example, I have the following text:
str='Some.Text {a1=v1 a2=v2}';
val=regexp(str, ?, 'match', 'once')
In "?" should be a like a pattern of special characters (lookaheads, lookbehinds, non-greedys, etc) but I don't know how to make it work to just extract everything inside {}.
Can someone help me?
Thanks in advance!
0 commentaires
Réponse acceptée
per isakson
le 23 Mai 2018
Modifié(e) : per isakson
le 23 Mai 2018
One way
>> str='Some.Text {a1=v1 a2=v2}';
>> cac = regexp( str, '(?<={)[^}]+(?=})', 'once', 'match' )
cac =
a1=v1 a2=v2
>>
[^}]+ is better than .+ because
'(?<=\{)[^}]+(?=\})' it doesn't hurt to escape {} if in doubt whether the are special characters.
3 commentaires
per isakson
le 23 Mai 2018
Modifié(e) : per isakson
le 23 Mai 2018
There are many good resources on the Internet. However, Matlab has it's own regular expression flavor. It's close to a subset of PCRE, (PERL Compatible RE). (Not the latest version of PRCE though.) Thus,
- the Matlab documentation
- Welcome to Regular-Expressions.info, The Premier website about Regular Expressions is good. It has a book review page.
- regular expression 101 is a free tool in the cloud. I use it for experimenting. But one must avoid features that are not in Matlab.
- There are some Matlab specific tools in the File Exchange
- Mastering Regular Expressions if you want to become an expert.
- and best of all is Understanding and Using Regular Expressions
per isakson
le 23 Mai 2018
Modifié(e) : per isakson
le 24 Mai 2018
btw:
xpr = [
'(?<={) ' ... % look behind for literal {
'[^}]+ ' ... % one or more of anything, but literal }
'(?=}) ' ... % look ahead for literal }
];
xpr( isspace(xpr) ) = [];
cac = regexp( str, xpr, ... );
I find this way of writing regular expressions good. It makes me think more and experiment less; it helps me avoid falling into an infinite "trial-and-error-loops".
- "space" is a bit of a problem. I write space as \x20
- The final look ahead isn't needed, since + is greedy
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Characters and Strings dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!