Effacer les filtres
Effacer les filtres

loop in a column to calculate max and min in a certain interval

2 vues (au cours des 30 derniers jours)
sud
sud le 28 Mai 2018
Commenté : jonas le 28 Mai 2018
i have a column that has 200 values of length for each volume. and there can be n no. of volumes. so i need to calculate the maximum and minimum of lengths for each volume and plot volume(vs)minlength and volume(vs)maxlength in the same plot. please suggest a loop and how to apply it. help is much appreciated.
  2 commentaires
jonas
jonas le 28 Mai 2018
What do you mean by volume? Can you provide an example? The problem is not clear to me.
Stephen23
Stephen23 le 28 Mai 2018
Modifié(e) : Stephen23 le 28 Mai 2018
sud's "Answer" moved here:
hi! i will attach a file. so its 1st column is volume and 16th column is length.

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Réponses (2)

KSSV
KSSV le 28 Mai 2018
Let V be your volume and A be other column.
[c,ia,ib] = unique(V) ;
N = length(c) ;
iwant = zeros(N,1) ;
for i = 1:length(c)
iwant(i) = mean(A(ib==i)) ;
end
  1 commentaire
sud
sud le 28 Mai 2018
Hi. It is working. thanks but maybe i didnt put my problem correctly. I want to apply a loop for thia program written below! (after every 200 lengths):
IdlCatalogue_Dir='C:\Users\yadav\Desktop\IDL_routine\OUTPUT_FILE\ROSETTE_S2_r5\';
File = 'ROSETTE_S2_r5_GeometricData.csv';
FF = fullfile(IdlCatalogue_Dir,File);
Type = strrep(File, '_GeometricData_TOT.csv', '');
Type = strrep(Type,'_','\_');
data = load(FF);
deq = data(end-199:end,16);
for i=1:length(deq)
minimum(i)=min(deq(1:i));
% i'th of maximum would be the max upto ith interval of deq .
end
x=1:1:200;
figure()
plot(x,maximum);
hold on;
plot(x,minimum); set(gca,'xscale','log');
xlabel('number of projections')
ylabel('Deq(µm)')
title('Variation of Max Deq and Min Deq with number of projections')

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jonas
jonas le 28 Mai 2018
Perhaps this will help...
data=readtable('ROSETTE_S2_R5_GeometricData.csv');
[volumes]=unique(data{:,1});
out=nan(2,length(volumes));
for i=1:length(volumes);
out(1,i)=min(data{data{:,1}==volumes(i),16});
out(2,i)=max(data{data{:,1}==volumes(i),16});
end
figure;
plot(volumes,out(1,:),...
volumes,out(2,:));
  9 commentaires
sud
sud le 28 Mai 2018
hi. so sorry for the bad format but i did try to select it and code it. i dont know why is it not taking the form of code!
jonas
jonas le 28 Mai 2018
I did some formatting and wrote this for you (see attached). All values are stored in maximum and minimum. You can choose which curve to plot by changing the variable id.
If you need anything else, please format the post correctly.

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