How to compare two matrix and then count each elements?

The elements of A will be checked and compared with B, with each element count S will increase and with each absence count R will increase.

A=[3 5 7]

B=[1 3 4 5 7]

[Paolo]

Can you please clarify what S and R are, and provide an expected output?

[Stephen23]

@suchismita: Please give more details, so that we can actually understand what you want.

What does "with each element count S will increase " mean: do you want to count how many elements A has, or how many elements B has, or how many elements of A as in B, or how many elements of B are in A?

What does "with each absence count R will increase" mean: do you mean elements of A missing from B, or elements of B missing from A, or missing from their own (somehow implied) sequences?

[suchismita]

sorry for late reply ... I want to count how many similar elements are there in A in compare to B. With each count S will increase and with each no R will.

[Stephen23]

"I want to count how many similar elements are there in A in compare to B"

That is what my answer does. You might also like to read about intersect and setdiff.

[suchismita]

S = nnz(ismember(A,B)) this is working but if I am changing value of A as A= [2 5 7] then I want my answer as S=2 and R=1

Answer 1

[Stephen23]

Some variety of these might do what you want (although those examples are not very enlightening)

>> S = nnz(ismember(A,B))
S =  3
>> R = nnz(ismember(B,A))
R =  3

[suchismita]

please help me. S value is OK but how can I count dissimilar value.

[Stephen23]

"but how can I count dissimilar value."

ismember returns a logical array. Negate that array to get the dissimilar values:

~ismember(...)

Answer 2

[Pratik Panchal]

It is not clear whether S and R are increasing if the values of A are same as values of B or regardless. Also what do you mean by 'absence'?

Anyway for the comparison You can use a for loop in this.

for k=1:length(A)
  for j=1:length(B)
     if A(k)==B(j);
       %Insert your condition here
     else
       %Insert your second condition here
   end
end