picking maximum difference across entries of row vectors, Part 2

18 vues (au cours des 30 derniers jours)
alpedhuez
alpedhuez le 6 Juin 2018
Now A is a table with the first column has the date data. (not a variale)
Please advise how to proceed in this general case.
for each row, take a difference between every possible pair of two elements in the row and returns the maximum difference
In a simpler case where A is a matrix, if A= [1 3 6 7 10], then B=[9].

Réponses (2)

Matt J
Matt J le 6 Juin 2018
result = max(A{:,2:end},[],2)-min(A{:,2:end},[],2)
  5 commentaires
Matt J
Matt J le 30 Avr 2021
Modifié(e) : Matt J le 30 Avr 2021
Well, if A is a matrix then max(A,[],2) will give the row-wise maximum of A and similarly for min(). So, if your goal is to obtain a row vector containing the differences between the row-wise max and min of a matrix A, then it would simply be,
p = ( max(A,[],2)-min(A,[],2) ).'
You don't need the indexing A(1:end,:) when A is a matrix. My original answer was intended for when A is a table.
Süleyman burak Dogaroglu
Süleyman burak Dogaroglu le 30 Avr 2021
thanks so much. now it is clear to me.

Connectez-vous pour commenter.


Aakash Deep
Aakash Deep le 6 Juin 2018
Hello,
In order to find out the maximum difference between two elements in a row vector, you can first sort it and then take the difference between the last and the first element.
vec = sort(A);
B = vec(end)-vec(1);
Hope this helps :)
  3 commentaires
Stephen23
Stephen23 le 6 Juin 2018
Modifié(e) : Stephen23 le 6 Juin 2018
@alpedhuez: If you post a follow-up question please put a link to the original question. It helps us to keep track of what information or answers you have already been given, and what extra clarifications or data you have given us about the question.
alpedhuez
alpedhuez le 6 Juin 2018
Thank you for letting me know.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Tags

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by