how I Found the minimum of function using the fminbnd ??
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f(x)=3x1+2x1x2+x2 such as 0.1≤ x1 ≤1 0.25 ≤ x2 ≤ 4 help me please thanks in advance
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Walter Roberson
le 7 Juin 2018
You cannot do that. fminbnd() can only be used for a function of a single variable.
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Walter Roberson
le 7 Juin 2018
fun = @(x) 3*x(1) + 2*x(1)*x(2) + x(2)
x0 = [.5 2.5];
A = [];
b = [];
Aeq = [];
beq = [];
lb = [0.1 0.25];
ub = [1 4];
x12 = fmincon(fun, x0, A, b, Aeq, beq, lb, ub)
x1 = x12(1); x2 = x12(2);
Torsten
le 7 Juin 2018
You can't. fminbnd is for functions of one variable - your f is a function of two variables.
Use "fmincon" instead.
Best wishes
Torsten.
7 commentaires
Torsten
le 7 Juin 2018
In principle, x0 is arbitrary.
But if you know an x0 that is feasible and near to the optimum, you should use it since you'll most probably get faster and more stable convergence towards the solution.
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