Saving a value from matrix B, indexed by matrix A
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
sprklspring
le 8 Juin 2018
Commenté : Majid Farzaneh
le 12 Juin 2018
Hello all, I have a pretty basic question which causes me problems. I have a 1x100 vector A. Each cell of this vector contains a different number, i.e. A(1,1) = 2010, A(1,2) = 3834, etc. Now, this values of a vector A are indeces, which index a column of vectors contained in all cells of a matrix B; matrix B is an 8x8 cell matrix, and each of its cells contain a 1x4000 vector of numbers. Could you tell me what is your idea of finding values indexed by the vector A in all of the cells of matrix B?
Update from below: all the numbers in 'indeces' vector are supposed to be found in each cell of the 8x8 matrix 'cell', i.e. I expect the output from each cell of the output matrix (the 'What you want' one) to be a vector of 1x132, providing the sample files I attached. Here it seems like I overwrite and save just the 132th value, since the output is just an 8x8 matrix of numbers, instead of 8x8 cell matrix of 1x132 vectors.
2 commentaires
James Tursa
le 8 Juin 2018
Please provide a short example of inputs and desired output(s) so we are clear what you want.
Réponse acceptée
Majid Farzaneh
le 8 Juin 2018
Modifié(e) : Majid Farzaneh
le 8 Juin 2018
Hi, you can use a for loop for B like this:
for i=1:numel(B)
...
end
Then, determine the index by A, like this:
idx=A(1,1); % for example
Get B values like this:
What_you_want(i)=B{i}(idx)
1 commentaire
Majid Farzaneh
le 8 Juin 2018
for i=1:numel(B)
idx=A(1,1); % for example
What_you_want(i)=B{i}(idx)
end
At the end you have 64 values in What_you_want matrix for 64 cells in B.
Plus de réponses (1)
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!