How to open .CSV file ?
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I want to open CSV file. (please find the attachment)
in the CSV file, I have date and time in the different column but I want to combine in one column. I have read with following code but I getting an error.
fbc = fopen('ABCD.CSV');
BC = textscan(fbc, '"%.f-%3.s-%.f", "%.f:%.f", %.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f,%.f');
fclose(fbc);
Réponses (2)
KSSV
le 13 Juin 2018
[num,txt,raw] = xlsread('ABCD.csv') ;
1 commentaire
Vishnu Dhakad
le 15 Juin 2018
Modifié(e) : Vishnu Dhakad
le 15 Juin 2018
Walter Roberson
le 15 Juin 2018
fmt = ['%{dd-MMM-yy}D%{HH:mm}D', repmat('%f', 1, 50)];
fbc = fopen('ABCD.CSV', 'r', 'n', 'UTF8');
BC = textscan(fbc, fmt, 'Delimiter', ',', 'CollectOutput', 1);
fclose(fbc);
dt = BC{1}+(BC{2}-dateshift(BC{2},'start','day'));
dt.Format = 'default';
numbers = BC{3};
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