how to find common elements of two matrices considering also the repeated values?
    5 vues (au cours des 30 derniers jours)
  
       Afficher commentaires plus anciens
    
    Gessica Cos
 le 13 Juin 2018
  
    
    
    
    
    Commenté : Gessica Cos
 le 14 Juin 2018
            Hello everybody, i would like to know how to find the position of elements of a matrix who are in another matrix. For example, letting i have two matrix A and B:
A= [2 1 2 
    3 2 5
    4 7 5
    4 8 10]
B= [4 7 5
    2 8 10
    4 1 2
    3 2 5]
I would like the output to provide the position of the elements of the B matrix that are present in the A matrix considering also repeated values.
For example "it finds in which position the element B (1,1) is present in the matrix A (:, 1), in which position the element B (2,1) is present in the matrix A (:, 1), in which position the element B (3,1) is present in the matrix A (:, 1) and so on ". So similarly for the other columns "find in which position the element B (1,2) is present in the matrix A (:, 2) etc"
Regarding the repetition I would like to make sure that if, for example, there are 3 repetitions in a column, each repetition will have an increasing order index, ie:
A= [ 2
4
4
4]
B=[4
2
4
4]
output=[2
1
3
4 ]
I tried to use the MATLAB function "intersect", but it give as outputs only the indexes of the columns whose values are not repeated.
for n=1:size(A,2)
      [C, idx1, idx2] = intersect( B(:,n), A(:,n), 'stable');
end
I do not know if I've been clear. Sorry.
0 commentaires
Réponse acceptée
  Stephen23
      
      
 le 13 Juin 2018
        
      Modifié(e) : Stephen23
      
      
 le 13 Juin 2018
  
      This is easy with sort, assuming that both A and B contain exactly the same elements:
>> A = [2;4;4;4];
>> B = [4;2;4;4];
>> [~,ida] = sort(A);
>> [~,idb] = sort(B);
>> [~,ida] = sort(ida);
>> [~,idb] = sort(idb);
>> ida(idb)
ans =
     2
     1
     3
     4
EDIT: use a simple loop to do matrices of any size. This is simpler because C is preallocated so we can index into it using idb:
A = [2,1,2;3,2,5;4,7,5;4,8,10];
B = [4,7,5;2,8,10;4,1,2;3,2,5];
C = nan(size(A));
for k = 1:size(A,2)
    [~,ida] = sort(A(:,k));
    [~,idb] = sort(B(:,k));
    C(idb,k) = ida;
end
And checking the output:
>> C % my code
C =
     3     3     2
     1     4     4
     4     1     1
     2     2     3
>> [3 3 2; 1 4 4; 4 1 1; 2 2 3] % requested output
ans =
     3     3     2
     1     4     4
     4     1     1
     2     2     3
7 commentaires
Plus de réponses (2)
  Image Analyst
      
      
 le 13 Juin 2018
        Try this:
A= [2 1 2
  3 2 5
  4 7 5
  4 8 10]
B= [4 7 5
  2 8 10
  4 1 2
  3 2 5]
% Find unique numbers in each of the two arrays.
ua = unique(A)
ub = unique(B)
% Check each number in B to see where it lives in A.
for k = 1 : length(ub)
  % Get this number from B
  thisB = ub(k);
  % Find out what rows and columns it shows up at in A
  [rows, columns] = find(A == thisB);
  % Save the number we were looking for into column 1 of the cell array.
  locations{k, 1} = thisB;
  % Save the locations that number was found into column 2 of the cell array.
  locations{k, 2} = [rows, columns];
end
celldisp(locations)
Be sure to read the FAQ https://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F so you understand what I did.
0 commentaires
Voir également
Catégories
				En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!


