why does simulink use the transfer function to simulate the step response?

1 vue (au cours des 30 derniers jours)

Afficher commentaires plus anciens

Giuseppe Alfieri le 15 Juin 2018

0
Lien

Utiliser le lien direct vers cette question

https://fr.mathworks.com/matlabcentral/answers/405807-why-does-simulink-use-the-transfer-function-to-simulate-the-step-response

Commenté : Giuseppe Alfieri le 15 Juin 2018

2 commentaires
Afficher AucuneMasquer Aucune

Aditya Adhikary le 15 Juin 2018

Both of these are separate blocks. Simulink does not "use" the transfer function, the model which you have designed or referred to here passes the output of the step function to the transfer function.

Giuseppe Alfieri le 15 Juin 2018

I'm sorry but i didn't explain myself well. My question was because the output of transfer function's block is the step response in the time domain and not in Laplace one?

Connectez-vous pour commenter.

Connectez-vous pour répondre à cette question.