How to find polynomial fiting on f(x) with known f(x1),f(x2​),f'(x1),f​'(x2)

1 vue (au cours des 30 derniers jours)
Iakovos Antonoglou
Iakovos Antonoglou le 18 Juin 2018
Commenté : John D'Errico le 18 Juin 2018
According to theory if two values for f on X1,X2 and the derivatives on X1,X2 you can use them to find a polynomial p(x) with p(x1)=f(x1), p(x2)=f(x2), p'(x1)=f'(x1), p'(x2)=f'(x2). I want to do that for f(x)=cos(2x^2) at 3.4=<x<=3.6 I have found the values for p and p' but i dont know how to combine them to get the polynomial (poly command is only useful for roots)
  2 commentaires
John D'Errico
John D'Errico le 18 Juin 2018
So, two points, with two pieces of information at each, will allow you to estimate 4 coefficients. So a cubic polynomial. What have you tried? If nothing, on what is very likely homework, why nothing? Why not try something? Then show what you try, and you might get some help. Otherwise, I would suggest using solve as a possibility. Or, you could do it using many other approaches, including pencil and paper.
John D'Errico
John D'Errico le 18 Juin 2018
Come on. What would you try?
I'll get you started.
x1 = 3.4;
x2 = 3.6;
syms x a b c d
P(x) = a*x^3 + b*x^2 + c*x + d;
F(x) = cos(2*x^2);
dF = diff(f);
dP = diff(P);
Now, you need to make some effort. What equations would you write? How would you solve them?

Connectez-vous pour commenter.

Réponse acceptée

KSSV
KSSV le 18 Juin 2018
f = @(x) cos(2*x.^2) ;
N = 100 ;
x = linspace(3.4,3.6,N) ;
y = f(x) ;
plot(x,y) ;

Plus de réponses (0)

Catégories

En savoir plus sur Polynomials dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by