How do I create a vector of n consecutive numbers spaced at with an interval of m between each group, without using a for loop?

18 vues (au cours des 30 derniers jours)
Is it possible to generate the following vector:
v=[1,2,3 ,6,7,8 ,11,12,13 ....]
without using a for loop? More generally, I would like to be able to generate groups of n consecutive numbers with an interval of m between each group (in the example n=3 and m=2).
Thank you in advance..

Réponse acceptée

Guillaume
Guillaume le 18 Juin 2018
Modifié(e) : Guillaume le 18 Juin 2018
numconsecutive = 3; %let's use better names than n, m, etc.
groupspacing = 2;
numgroups = 5;
v = reshape((1:numconsecutive)' + (0:numgroups-1)*(numconsecutive+groupspacing), 1, [])
This requires R2016b or later

Plus de réponses (1)

Honglei Chen
Honglei Chen le 18 Juin 2018
Modifié(e) : Honglei Chen le 18 Juin 2018
Here is one possible solution
N = 9;
n = 3;
m = 2;
x = buffer(1:N,n);
x = x+(0:size(x,2)-1)*m;
x(1:N).'
HTH
  1 commentaire
Seb Long
Seb Long le 18 Juin 2018
Many thanks for your answer! This works fine but I accepted the answer above as it runs faster. Thanks again..

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