How I equate the arrangement of elements two matrices???

I have two matrices with the same size 5x5, the element of the two matrices is 0 and 1 but arrange of the element is different, and now i want to equate the element of the two matrices, arrangement of elements in matrices B must same with arrangement of elements in matrices A , without eliminate the elements in matrices B

If you know the way please help me....

[Walter Roberson]

What would the expected answer be?

At first I thought perhaps you were asking for the permutation matrix between the two, but we can see that B is not a permutation of A, because A has both rows and columns that are all 1's but B has no rows or columns that are all 1's.

[Immanuel Saragih]

Yes, A and B is not related matrix, it is different, i just want the position of 0 and 1 in matrix B same with matrix A eventhough not all element

Answer 1

[Walter Roberson]

[R, C] = find(A == B);

[Immanuel Saragih]

Thanks for your answer Mr.Walter....

but the answer i expected is matrix that size 5 x 5 and the arrangement elements of the matrix is same with matrix A. in the other words i expected how to change position arrangement of elements in matrix B same with A not find the similarity in the two matrix.

The element in matrix B will change position according with matrix A or if we want to make new matrix the matrix must size 5 x 5 and the element must same with matrix A

According to your answer it is result vector one row not matrix and the vector is tell in what position the element between two matrix is same

[Walter Roberson]

Count the number of 1's in A; you will see there are 16.

Count the number of 1's in B; you will see there are 13.

It is not possible to re-arrange B to be the same as A -- not unless you allow duplication.

[Immanuel Saragih]

i expected B same with A eventhough not all it's element.....

So how about duplication??

do you know the way if i allow duplication??

[Image Analyst]

"i expected B same with A eventhough not all it's element....." I hope you can see that this makes no sense whatsoever. If it's the same, all elements match. If all elements don't match, it's not the same.

[Immanuel Saragih]

So how if the number of each element 0 and 1 is same in A and B.... could you told me the way??

Answer 2

[Image Analyst]

Why can't you simply do

B = A;

This will make the "arrangement of elements in matrices B must same with arrangement of elements in matrices A" just like you asked for.

[Immanuel Saragih]

I have tried that but it is make error

[Image Analyst]

Sorry, but only Walter has the Crystal Ball Toolbox at the moment. For the rest of us mere mortals you'll have to tell us what the error says.

[Image Analyst]

By chance, to you possibly just want to set the 1 elements of A to 1 in B, like this:

B(A) = 1;

[Walter Roberson]

More likely

 B(A==1) = 1;

[Walter Roberson]

The Crystal Ball Toolbox is saying, "Concentrate and ask again."