How to subtract rows when there is a value repeated more than once ?

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Benjamin Dupre
Benjamin Dupre le 25 Juin 2018
Commenté : Benjamin Dupre le 25 Juin 2018
I want to fill the interval item (Int_item) variable with the difference between the present trial (trial) and the past trial where the observation (obs) appeared. Leave it with a zero for those observations that are not repeated (appereance_number [ap_n] >1).
a =
270×9 table
onset ap_n obs response eval rtim trial class Int_item
_______________ ____ ___ ________ ____ ____ _____ _____ ________
"_10:50:57.315" 1 1 1 1 886 1 0 0
"_10:51:21.293" 2 1 0 0 0 7 0 0
"_10:53:57.247" 3 1 4 1 825 46 0 0
"_10:51:01.313" 1 2 1 1 733 2 0 0
"_10:51:29.303" 2 2 4 1 1478 9 0 0
"_10:54:09.242" 3 2 4 1 948 49 0 0
"_10:51:05.311" 1 3 1 1 929 3 0 0
"_10:51:33.301" 2 3 4 1 904 10 0 0
"_10:54:25.237" 3 3 4 1 1687 53 0 0
"_10:51:09.310" 1 4 1 1 866 4 0 0
"_10:51:37.300" 2 4 4 1 758 11 0 0
"_10:54:33.234" 3 4 4 1 740 55 0 0
"_10:51:13.309" 1 5 1 1 1028 5 0 0
"_10:51:45.296" 2 5 4 1 1283 13 0 0
"_10:54:45.230" 3 5 4 1 811 58 0 0
It aiming to end up with something similar to this in the Int_item column.
a =
270×9 table
onset ap_n obs response eval rtim trial class Int_item
_______________ ____ ___ ________ ____ ____ _____ _____ ________
"_10:50:57.315" 1 1 1 1 886 1 0 0
"_10:51:21.293" 2 1 0 0 0 7 0 6
"_10:53:57.247" 3 1 4 1 825 46 0 39
"_10:51:01.313" 1 2 1 1 733 2 0 0
"_10:51:29.303" 2 2 4 1 1478 9 0 7
"_10:54:09.242" 3 2 4 1 948 49 0 40
"_10:51:05.311" 1 3 1 1 929 3 0 0
"_10:51:33.301" 2 3 4 1 904 10 0 7
"_10:54:25.237" 3 3 4 1 1687 53 0 43
"_10:51:09.310" 1 4 1 1 866 4 0 0
"_10:51:37.300" 2 4 4 1 758 11 0 7
"_10:54:33.234" 3 4 4 1 740 55 0 44
"_10:51:13.309" 1 5 1 1 1028 5 0 0
"_10:51:45.296" 2 5 4 1 1283 13 0 8
"_10:54:45.230" 3 5 4 1 811 58 0 43
This is the code from what I'm trying:
a = DATA{1,1}; % CREAT TEMP VAR
a.class = zeros(270,1); % add a new collumn
a.Int_item = zeros(270,1); % add a new collumn
a = sortrows(a,[3 2]); % making it easy to find interval of items between rep
for i = 2:height(a)
a.Int_item = a.trial(i)-a.trial(i-1)
end
To assign to or create a variable in a table, the number of rows must match the height of the table.
I hope the question is clear.
All best,

Réponse acceptée

Ankita Bansal
Ankita Bansal le 25 Juin 2018
Modifié(e) : Ankita Bansal le 25 Juin 2018
Hi, there are some errors in for loop. The size of a.Int_item is 270x1 while that of a.trial(i)-a.trial(i-1) is 1x1. Also, you have not inserted the condition of ap_n>1.
for i = 2:height(a)
if a.ap_n(i)>1
a.Int_item(i) = a.trial(i)-a.trial(i-1);
end
end
  1 commentaire
Benjamin Dupre
Benjamin Dupre le 25 Juin 2018
Hi Ankita, you are right. revising another answer I came around this expression to avoid that problem.
a_z = a.trial(2:end)-a.trial(1:end-1)

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