how do i get the last points of every 100 points from a 1000 point graph
7 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Carlos Nunez
le 6 Juil 2018
Modifié(e) : per isakson
le 6 Juil 2018
x=0:1000
y=sin(x)
for N=0:100:length(x)
if N>N-50
N
end
end
this is what i have and i know its not right so please help
4 commentaires
Image Analyst
le 6 Juil 2018
Huh? Is Carlos deleting his responses? All I see is this:
"how do i get the last points of every 100 points from a 1000 point graph"
x=0:1000
y=sin(x)
for N=0:100:length(x)
if N>N-50
N
end
end
Which is very confusing in itself.
Réponse acceptée
per isakson
le 6 Juil 2018
Modifié(e) : per isakson
le 6 Juil 2018
"how do i get the last points of every [sequence of] 100 points from a [sequence of] 1000 point[s]" That's my interpretation of your question.
What about
>> x((100:100:1000))
ans =
99 199 299 399 499 599 699 799 899 999
>> y((100:100:1000))
ans =
-0.9992 -0.8818 -0.5216 -0.0177 0.4910 0.8645 1.0000 0.8601 0.4834 -0.0265
>>
Notice
>> length(x)
ans =
1001
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Directed Graphs dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!