2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. Write a function called smallest_multiple that returns a uint64, the smallest positive number that is evenly divisible by all of the numbers fr
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function a=smallest_multiple(n)
a=1;
x=mod(a,(1:n));
while sum(x)~=0
a=a+1;
x=mod(a,(1:n));
if a>intmax('uint64')
a=0;
else
continue
end
end
a=uint64(a);
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