How can I make a cartesian graph into a polar graph?
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I have a 16x9 array, of which the last 8 columns are 1x37 matrices (for angles 0:5:180), so the end goal is to get 16 different graphs.
The last 6 columns were calculated by me, in radians. The columns 2 and 3 were read from a file, in degrees, so I convert those to radians and then try to plot them together, against the x value shown.
figure(1)
hold on
for i=0:5:180
x((i/5)+1)=(i*pi)/180;
end
for i=1:length(DataAll)
for j=2:3
DataAll{i,j}=DataAll{i,j}*pi/180;
end
end
for i=2:9
polarplot(x,DataAll{1,i});
end
Hopefully this is enough information to go on, if not I can provide more.
6 commentaires
dpb
le 13 Juil 2018
" theta to be the x from above, and the r values are the values within the 1x37"
So the idea is 16 figures with 8 lines on each?
How about attaching a .mat file with the data array for folks to play at...the polarplot is a pretty new beastie...
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