i want to create A 3-D matrix and i want a pixel to be increasing by 1 in each of the matrix. how can i do that

i want the 3rd row and 3rd column in each matrix to be increasing with every iteration. i hvave done this but it is not working. help, I am new to matlab

m=zeros(10,10,30);  %define 3-D 10 by 10 by 30 matrix
n=30;               %number of matrix
for k=1:n
    t=0:1.0;    %specify the value a pixel will take in each iteration
    m(:,:,k)(3,3)=t;    %the 3rd rown and 3rd column in each matrix will increase by t
    display(m(:,:,k))
    k=k+1;
    t=t+0.1;
end

[Folakemi Omotoye]

Help please

Answer 1

[Geoff Hayes]

Folakemi - the sytax

 m(:,:,k)(3,3)=t;

is invalid. Do you really mean for t to be a 1x2 array with

 t = 0:1.0;

or do you want it to be a 1x10 (or 10x1) array with elements evenly distributed from 0 to 1.0? If the latter, then try

 t = linspace(0,1,10);

and do

 t = linspace(0,1,10);
 for k=1:n
    m(3,:,k) = t;
    m(:,3,k) = t';
 end

If you want to increaser t for subsequent iterations, then you would need to do

 t = linspace(0,1,10);
 for k=1:n
    m(3,:,k) = t;
    m(:,3,k) = t';
    t = t + 1;
 end

[Folakemi Omotoye]

i want the value of t to be evenly spaced and the value of the 3rd row 3rd column in each matrix to have the increasing value of t i.e only the element (3,3) in each matric will be changing and it will have the value of t (which will be changing for each iteration as well.

[Folakemi Omotoye]

the linspace command will not work for me.i want the values between 0 and 1 to be divided into 30 intervals for each of the matrix

[Geoff Hayes]

Perhaps this

 t = 0;
 for k=1:n
    m(3,:3,k) = t;
    t = t + 1/n;
 end

or

 t = linspace(0,1,n);
 for k=1:n
    m(3,3,k) = t(k);
 end

[Folakemi Omotoye]

the second part worked. Thank you very much