difference result with same equation

my commands

bhp=100*ones(10,1);

bht=[500;500;500;500;500;300;300;300;300;300];

p= @(bhp,bhT) bhp + g*dz.*rho(bhp,bhT);

tried to validation p(bhp,bhT).*bhp + g*dz.*rho(bhp,bhT)

result ans =

   1.0e+09 *

   -2.2263
   -2.2263
   -2.2263
   -2.2263
   -2.2263
   -4.7130
   -4.7130
   -4.7130
   -4.7130
   -4.7130

how can be i got difference result if i assume a=g*dz.*rho(bhp,bhT); a =

   1.0e+07 *

   -2.2042
   -2.2042
   -2.2042
   -2.2042
   -2.2042
   -4.6664
   -4.6664
   -4.6664
   -4.6664
   -4.6664
b=bhp;
c=a+b
result
c =

   1.0e+07 *

   -2.2042
   -2.2042
   -2.2042
   -2.2042
   -2.2042
   -4.6664
   -4.6664
   -4.6664
   -4.6664
   -4.6664

anyone can help me?

[Aquatris]

because at the top results you are evaluating

p(bhp,bhT).*bhp + g*dz.*rho(bhp,bhT)

and at the bottom

 bhp + g*dz.*rho(bhp,bhT)

This can further be proved by looking at the results and seeing the relation

   100*(bottom results)+a = (top results)

Also your code is missing g and rho, maybe other variables aswell for me to run it on my Matlab to further help.

Answer 1

[vaya putra]

thank you very much, i understand

Answer 2

[vaya putra]

actually i want calculate this equation,

that why i define by my self bhp and bhT, ho to prove aot calculate bhp,bhT if i get value (bhp and bhT)

p = @(bhp,bhT) bhp + g*dz.*rho(bhp,bhT);